3/4[8t-12]=6(t-1)

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Solution for 3/4[8t-12]=6(t-1) equation: 


Oblicz to!

(9/4)*t^-1 = 0

f/2-4 = 1

x^2*((9*x^5)/27) = 0

-3/4 = (1/4)*u-(4/3)

3*(x-(1/2))-((1/4)*(x-(1/3))) = 1/3

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